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Thread: Integration by trig substitutions.

  1. Jul 9th 2009, 11:56 AM #1
    pantsaregood
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    Integration by trig substitutions.

    Edit: stupid mistake. I didn't have anything wrong to begin with.
    Last edited by pantsaregood; Jul 9th 2009 at 12:25 PM.
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  2. Jul 9th 2009, 12:06 PM #2
    pomp
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    Just substitute x = 3\sin{\theta}

    then dx = 3\cos{\theta}d\theta

    You should end up at \int \cot^2{\theta} d\theta
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  3. Jul 9th 2009, 12:16 PM #3
    pantsaregood
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    That's... exactly where I am now. My substitutions were different than yours, but they give the same exact problem.
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