Edit: stupid mistake. I didn't have anything wrong to begin with.
Last edited by pantsaregood; Jul 9th 2009 at 12:25 PM.
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Just substitute $\displaystyle x = 3\sin{\theta}$ then $\displaystyle dx = 3\cos{\theta}d\theta$ You should end up at $\displaystyle \int \cot^2{\theta} d\theta$
That's... exactly where I am now. My substitutions were different than yours, but they give the same exact problem.
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