An equilateral triangle has sides of 0.16 m. Charges of -8.8, +8.0, and +1.7 µC are located at the corners of the triangle. Find the magnitude of the net electrostatic force exerted on the 1.7-µC charge.

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- Jul 9th 2009, 05:41 AMwilliammagnitude
**An equilateral triangle has sides of 0.16 m. Charges of -8.8, +8.0, and +1.7 µC are located at the corners of the triangle. Find the magnitude of the net electrostatic force exerted on the 1.7-µC charge.** - Jul 9th 2009, 10:55 AMBhajun
Definitely the wrong forum.

But, all you need is Coulomb's law.

$\displaystyle F = \frac{1}{4\pi\epsilon_0}\left( \frac{q_1q_2}{r_2^2} + \frac{q_1q_3}{r_3^2} \right)$

Since its an equilateral triangle, r is the same for each:

$\displaystyle F = \frac{q_1}{4\pi\epsilon_0 \cdot r^2}\left( q_2 + q_3\right)$

You can do the plug and chug.