1. ## Funtions and Primitives

Hey there!
I was given the following exercise:

The function $h:\mathbb{R} \longrightarrow \mathbb{R}$ is consistent with the following:
$h'(x)=(3x-2)\sqrt{1+|2x|}$

and

$h(1)=0$.

Calculate $h(-1)$.

So I have tried to calculate the primitive of the function h'(x) so I could get to h(x) but everything I've tried calculating doesn't give me h(1)=0. Even inputing h'(x) into Wolfram Integrator gives me a certain h(x) that doesn't comply with h(1)=0.

Could you please have a look at it and let me know how you'd do it?

2. Originally Posted by mei
Hey there!
I was given the following exercise:

The function $h:\mathbb{R} \longrightarrow \mathbb{R}$ is consistent with the following:
$h'(x)=(3x-2)\sqrt{1+|2x|}$

and

$h(1)=0$.

Calculate $h(-1)$.

So I have tried to calculate the primitive of the function h'(x) so I could get to h(x) but everything I've tried calculating doesn't give me h(1)=0. Even inputing h'(x) into Wolfram Integrator gives me a certain h(x) that doesn't comply with h(1)=0.

Could you please have a look at it and let me know how you'd do it?
You will be getting some h(x), and hence some h(1). Suppose you are getting h(1)=4

then change your h(x) like this
your new h(x) will be h(x)-4
See that h(x) and h(x)-4 have the same h'(x)