1. ## Simple equations

Can anyone explain how does the $s$ variable ends up as a denominator? I cant really understand the last equality.

$dq=Tds=>\int_{i}^{f}dq=\int_{i}^{f}Tds$ aproximately equal to $\overline{T}\int_{i}^{f}ds<=>\overline{T}=\frac{_i q_f}{s_f-s_i}$

2. you'r solving for Tbar

q = Tbar(sf-si)

divide by sf -si to solve for T bar