if f(6)= dne but tends to negative infinity, then there is no absolute minimum because you can always find a smaller number within the interval
For a " Find all extrema; local, end point, absolute points"
I'll just post the final answer cause I just want an explanation for something...
F(-2) = 2
F(0) = 2
F(1) = -2
F(3) = 38
F(6) = DNE
So I got the answers
F(-2) is the end point max.
F(1) is the local min.
F(3) is the local max, absolute max.
There is no end point min because F(6) is DNE.
I got the same answer as the book, but the book also says that there is no absolute min. Why is F(1) not the absolute min as well? is it because it's the only low point in the sine line?