hi
can some one please check this for me
need to evaluate integral x(7-3x^2) for x=6 to x=4
i did this 1/2(7-3x^2)(2x)dx
1/2 *1/2(7-3x^2)^2+c
1/4(7-3x^2)^2+c
then for x=6 to x=4
1/4(7-3(6)^2-1/4(7-3(4)^2
am i on the right track ?
wayne
hi
can some one please check this for me
need to evaluate integral x(7-3x^2) for x=6 to x=4
i did this 1/2(7-3x^2)(2x)dx
1/2 *1/2(7-3x^2)^2+c
1/4(7-3x^2)^2+c
then for x=6 to x=4
1/4(7-3(6)^2-1/4(7-3(4)^2
am i on the right track ?
wayne
Don't integrate - balloontegrate!
Balloon Calculus Forum