hi
can some one check this please
i have h(u)=sin^2 (3/4u)
i used sin^2 u = 1/2(1-cos(2u))
i made p=3/4u and sin^2 (p) = 1/2(1-cos(2p))
=1/2(1-cos(3/2u))
=1/2-1/2cos(3/2u))
integate=1/2u-3/4sin(3/2u)+c
many thanks
wayne
Are you sure you got the point, here? 'Flipping' is involved, maybe, but in order to cancel the three-over-two fraction that comes as the derivative of 'three over two u', which is the inner function of a chain rule process.
Maybe you did entirely get the point - then forgive me this diagram opportunity...
As usual, straight continuous lines differentiate downwards (/integrate up), the straight dashed line similarly but with respect to the dashed balloon expression - so that the triangular network on the right satisfies the chain rule for differentiation.
The 'flipping' would be, perhaps, the multiplying of the one-over-two fraction by the reciprocal of three-over-two.
Don't integrate - balloontegrate!
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