I need help with this problem...

prove that the limit

such that when is rational; when is irrational

does not exist. Thanks to anyone who helps!

yes, I think I should learn LaTex...

(Nerd)

Printable View

- Jul 2nd 2009, 05:42 PMChokfullPrecise definition of a limit
I need help with this problem...

prove that the limit

such that when is rational; when is irrational

does not exist. Thanks to anyone who helps!

yes, I think I should learn LaTex...

(Nerd) - Jul 2nd 2009, 05:59 PMPlato
You have some real issues with notation.

What you have posted is almost unreadable.

If you want to receive real help here then you should learn LaTex.

Your function is .

Now you need to recall that**any neighborhood of 0 contains infinitely many of both rational and irrational numbers.**

There has got to a contradiction there if that limit exists. - Jul 2nd 2009, 08:28 PMBruno J.
This is easy with sequences.

Show that there is a sequence of irrational points converging to 0; then if is continuous at 0 we must have ; but hence is not continuous at 0 (or anywhere for that matter).

As a side note, a funny thing is that the function

is continuous at 0.

I also second Plato's advice to learn LaTeX. (At least you're trying a bit!) - Jul 2nd 2009, 10:42 PMmatheagle
Both sets are dense.

So any interval about zero, no matter how small, will always contain rationals and irrational numbers.

Thus for all x in f(x) will be both 0 and 1.