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Math Help - Accelerstion in a frame of reference moving along the x-axis with speed u

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    Acceleration in a frame of reference moving along the x-axis with speed u

    x'= (x-ut)/[{1-(u/c)^2}^(1/2)] ---->I

    t'= [t-ux/(c^2)]/[{1-(u/c)^2}^(1/2)] ---->II

    Find the 2nd order derivative of x' w.r.t. t'.
    Actually, Newton's laws of motion should have the same form in both a stationary frame and a frame moving with a uniform velocity. For that, the 2nd order derivative of x' w.r.t. t' should be [{1-(u/c)^2}^(1/2)]*(d2x/dt2), since m'=m/[{1-(u/c)^2}^(1/2)]. But it's not coming. May be, I'm making some mistake. Please help me out.
    Last edited by nirmalya basu; January 2nd 2007 at 02:50 AM.
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