Originally Posted by

**goldenroll** well I think its more that I'm just getting confused (summer school cal just feels like huge load of information and hard to remember the rules) but here is what I gotten for my first question.

x/2(8-x^2) right and then I times that by 2(8-x^2)/2(8-x^2) which is part of the chain rule (thinking this is were I'm messing up, then 2x(8-x^2)/2(8-x^2) then the locals are x=0, plus or minus sq. 8?

2.

for the second question I did this 1/3 x^(-2/3) (x+8) + x^(1/3)1 = 4x+8/3x^(2/3) = 4(x+2)/3x^(2/3) = x= 0,-2

a. Incr. (-2,0), (0,inf.), Decr. on (-inf.,-2)

b. min at -2

c. Still don't quiet understand how to do ab.