Is this right for the derivative of arcsin(2x)? = 1/√(1 - 4x²)
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Originally Posted by offahengaway and chips Is this right for the derivative of arcsin(2x)? = 1/√(1 - 4x²) missing a "2" in the numerator (derivative of 2x)
thanks
is the differential of √(1 - 4x²) =1/2(1 - 4x²)^-1/2
hello you've forgotten the differential of $\displaystyle 1-4x^{2}$
Which is -8x?
While im here can this be simplified? arcsin(2x)1/2(-8x)^-1/2
hello you mean this : $\displaystyle \frac{asin\left( 2\,x\right) }{4\,\sqrt{2}\,\sqrt{-x}}$ $\displaystyle ?$
i mean this arcsin(2x)[1/2(-8x)^-1/2] can the above be simplified?
try to expand what is in $\displaystyle [$ $\displaystyle ]$,you'll have the same result,and it's already simplified. (or probably i went wrong)
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