Hi,
I was wondering how one would go about finding the domain of a 3-dimensional surface. For example, if the equation was f(x,y) = (sqrt(x + 2y + 1)) * (sqrt(x - 2y + 1)) * (ln(1-sqrt(tan(x^2 + 2x - 4y^2)))) what would the domain be? Thanks!
Hi,
I was wondering how one would go about finding the domain of a 3-dimensional surface. For example, if the equation was f(x,y) = (sqrt(x + 2y + 1)) * (sqrt(x - 2y + 1)) * (ln(1-sqrt(tan(x^2 + 2x - 4y^2)))) what would the domain be? Thanks!
find the domain for the first and the second and third each one alone then find the intersect of the result you have
you should know that the square root of the negative numbers is undefined and ln the natural log is the same and for the tan(s) ''s is arbitrary function'' cos(s) should not equal zero
the domain of the first one for the second
for the third
so
and
tan is positive in the first and the third quarter so
if
this in the first quarter in the third
in general
so
n integer
lats return to the domain of the first and the second
since the both of them is positive
forget it
the domain is
that is the way you can find the domain