Consider the solid obtained by rotating the region bounded by the given curves about the y-axis. so i dont think this is the washer method y = (x/5)^2
Last edited by XplicitZero; Jun 24th 2009 at 06:26 PM.
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Originally Posted by XplicitZero Consider the solid obtained by rotating the region bounded by the given curves about the y-axis. Okay, so i think this is the washer method( where the inside is empty) so its " Pi ( outer radius)^2 - Pi ( Inner radius)^2 " Can someone please explain to me how i can find both the radii disk method ... $\displaystyle V = \pi \int_0^2 (5\sqrt{y})^2 \, dy $
oh Okay Got it. ans is 50pi =] thank you skeeter
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