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Math Help - differentiate y= arcosh (4+3x)

  1. #1
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    differentiate y= arcosh (4+3x)

    differentiate y= arcosh (4+3x)

    could anyone help me please . what differentiation rule do i use with this equaiton and what answer should i get please thankyou !!!!
    Last edited by mr fantastic; June 30th 2009 at 03:07 AM. Reason: Added post title to main body of post
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  2. #2
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    Hello there,

    I assume you mean:  \frac{d}{dx} ( cos^{-1}(4 + 3x)) .

    Recall that  \frac{d}{dx} cos^{-1}(x) = -\frac{1}{\sqrt{1 - x^2}} .

    Be sure to use Chain Rule when differentiating.

    Good luck! This should be enough information.
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  3. #3
    MHF Contributor matheagle's Avatar
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    No, this is the inverse of hyperbolic cosine.

    Hyperbolic cosine is

    \cosh x={e^x+e^{-x}\over 2} and \sinh x={e^x-e^{-x}\over 2}

    See http://en.wikipedia.org/wiki/Hyperbolic_cosine.

    The inverse of cosh can be obtained via algebra, letting w=e^x.

    But you can see the derivative of the inverse of cosh at that page, then via the chain rule you can solve this problem.
    Last edited by matheagle; June 24th 2009 at 11:37 PM.
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  4. #4
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    Quote Originally Posted by lukyleo26 View Post
    differentiate y= arcosh (4+3x)

    could anyone help me please . what differentiation rule do i use with this equaiton and what answer should i get please thankyou !!!!
    Asked in this thread: http://www.mathhelpforum.com/math-he...lp-please.html

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