The equation sin xy = y defines y implicitly as a function of x.
Find the slope y'(pi/3,1/2) at the point x=pi/3, y=1/2.
i know that y' = (ycos(xy))/(1-xcos(xy))
but i just dont know how to solve the problem when i plug in x and and y to find the slope
please help
ty
The derivative of a function evaluated at a given point is the slope of the line tangent to the graph of the function at that point.
So, You've got a derivative, and you've got a point. Evaluate the derivative at that point and that will give the slope.
i.e. Plug in wherever you see an x, and whereever you see a y.
Note* .