The equationsin xy = ydefines y implicitly as a function of x.

Find the slope y'(pi/3,1/2) at the point x=pi/3, y=1/2.

i know that y' = (ycos(xy))/(1-xcos(xy))

but i just dont know how to solve the problem when i plug in x and and y to find the slope (Blush)

please help

ty:)