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**VonNemo19** Suppose that $\displaystyle f$ and $\displaystyle g$ are functions such that:

$\displaystyle f(2)=-1, f'(2)=4, f''(2)=-2, g(2)=-3, g'(2)=2, g''(2)=1$.

Find the value of each of the following at $\displaystyle x=2$:

a) $\displaystyle (2f-3g)'$

b) $\displaystyle (2f-3g)''$

c) $\displaystyle (fg)'$

Would I be right by saying that I need to do something like this:

$\displaystyle (2f-3g)'=2f'-3g'=2(4)-3(2)=2$ ? Mr F says: Yes.

Could someone give a small lecture on what's happening here?

Thankx.