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Math Help - evaluate the integral

  1. #1
    Newbie
    Joined
    Feb 2009
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    7

    evaluate the integral

    Here is the integral: sqrt[x^2 - 9]/x^2.

    I know the answer (ln (x + sqrt[x^2+9]) - (sqrt[x^2 - 9]/x))

    How does this answer come about? I have tried using the trig functions and I am getting no where close to the answer.

    Cheers!
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  2. #2
    Super Member malaygoel's Avatar
    Joined
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    India
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    648
    have you tried x=3sec\theta
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