Here is the integral: sqrt[x^2 - 9]/x^2. I know the answer (ln (x + sqrt[x^2+9]) - (sqrt[x^2 - 9]/x)) How does this answer come about? I have tried using the trig functions and I am getting no where close to the answer. Cheers!
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have you tried$\displaystyle x=3sec\theta$
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