
Originally Posted by
nein12
Oops... my bad.
If lim x->a g(x) = infinity and g(x) < or equal to f(x) for x -> a, then limx-> a f(x) = infinity
Prove, using the formal definition of limits, each of the statement is true.
So... that's the question. Honestly, I never had to answer this kind of questions. It's usually applications format or equation format.
Another one is limx->infinity f(x) = -infinuty and c > 0, then limx ->infinity c f(x) = - infinity
Not sure which rules to use, but I can reason... that f(x) is a negative infinity... times bu any constant positive number is still negative infinity. I am not sure if there are any "specific rules".
So we wish to show that if
and
as ?
?, then =\infty)
Well, for infinite limits the definition states:
Let g(x) be a function that is defined on an interval containing a, except possibly at a. Then we say that
if for every number M>0, there is some number

such that
>M)
whenever

So then the proof is straight forward
if
>M)
for every x arbitrarily close to a, then
>g(x))
for every value of x arbitrarily close to a
Therefore
>M)
whenever
