Originally Posted by

**nein12** Jhevon,

Thanks a lot for your time and effort. I have a bit of trouble grasping some of your answers...

I could substitute the x variables with zero to get that, but I used the graphing calculator to double check this answer. From what I see, the graph domain for square root (x-x^2) is 0 < or equal x < or equal 1. As you see, 0 is at the very left end of the function.

In order for limit as x->0 to exist, x->0+ and x->0- must be equal to each other. x->0+ exists because function from 1 to 0 is continuous. x->0- however cannot be continuous as any values less than 0 does not exist.

Hence, limit for x->0+ exists (0, of course) and limit for x->0- is undefined. Hence, the overall limit does not exist.

Similar argument for the square root (1-x) as x -> 1+

Am I just being paranoid, or is there a flaw in my arguement? Again, I would appreciate if you could get back to me.

nein12