1. ## Implicit differentiation help please

I need to find dy/dx

$y^2=lnx$

Thanks
Jason

2. Hello there,

Simply differentiate both sides, and then isolate $\frac{dy}{dx}$.

Good luck!

3. Originally Posted by scherz0
Hello there,

Simply differentiate both sides, and then isolate $\frac{dy}{dx}$.

Remember that $\frac{dy}{dx} \ln x = \frac{1}{x} dx$.
No. The $\frac{d\ln x}{dx}= \frac{1}{x}$. What $\frac{dy}{dx} \ln x$ is depends on what function y is of x.

Good luck!

4. Originally Posted by Darkhrse99
I need to find dy/dx

$y^2=lnx$

Thanks
Jason
You know, I hope, that the derivative of $y^2$ with respect to y is 2y. Use the chain rule to find the derivative of $y^2$ with respect to x. Set that equal to the derivative of ln x with respect to x and solve for dy/dx.

5. hi
$\frac{dy}{dx} = \frac{1}{2\,x\,\sqrt{log\left( x\right) }}$