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Math Help - Implicit differentiation help please

  1. #1
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    Implicit differentiation help please

    I need to find dy/dx

    y^2=lnx

    Thanks
    Jason
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  2. #2
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    Hello there,

    Simply differentiate both sides, and then isolate  \frac{dy}{dx} .

    Good luck!
    Last edited by scherz0; June 17th 2009 at 11:52 AM. Reason: Thanks, HallsofIvy.
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  3. #3
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    Quote Originally Posted by scherz0 View Post
    Hello there,

    Simply differentiate both sides, and then isolate  \frac{dy}{dx} .

    Remember that  \frac{dy}{dx} \ln x = \frac{1}{x} dx  .
    No. The \frac{d\ln x}{dx}= \frac{1}{x}. What \frac{dy}{dx} \ln x is depends on what function y is of x.

    Good luck!
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  4. #4
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    Quote Originally Posted by Darkhrse99 View Post
    I need to find dy/dx

    y^2=lnx

    Thanks
    Jason
    You know, I hope, that the derivative of y^2 with respect to y is 2y. Use the chain rule to find the derivative of [itex]y^2[/itex] with respect to x. Set that equal to the derivative of ln x with respect to x and solve for dy/dx.
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  5. #5
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    Smile

    hi
    your answer should be equal to :
    \frac{dy}{dx} = \frac{1}{2\,x\,\sqrt{log\left( x\right) }}
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