Hello guys,
I need help with two of the most weird equations i have ever seen.
Problem 1:
Solve the initial value problem
xy' + 3y = x^7, y'(0) = 3.
Problem 2:
Solve the initial value problem
(x^2)y' + y = 1, y(1) = 2.
Thanks, in advance.
Hello guys,
I need help with two of the most weird equations i have ever seen.
Problem 1:
Solve the initial value problem
xy' + 3y = x^7, y'(0) = 3.
Problem 2:
Solve the initial value problem
(x^2)y' + y = 1, y(1) = 2.
Thanks, in advance.
These quations aren't very weird at all. You need to use the integrating factor method for both. They just need a little re-arranging first.
$\displaystyle xy' + 3y = x^7$
divide both sides by x
$\displaystyle y' + \frac{3}{x}y = x^6$
Then follow the steps in this post
http://www.mathhelpforum.com/math-he...equations.html