Hello guys,

I need help with two of the most weird equations i have ever seen.

Problem 1:

Solve the initial value problem

xy' + 3y = x^7, y'(0) = 3.

Problem 2:

Solve the initial value problem

(x^2)y' + y = 1, y(1) = 2.

Thanks, in advance.

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- Jun 15th 2009, 08:20 PMtapiaghectorFirst order differential and linear equations
Hello guys,

I need help with two of the most weird equations i have ever seen.

Problem 1:

Solve the initial value problem

xy' + 3y = x^7, y'(0) = 3.

Problem 2:

Solve the initial value problem

(x^2)y' + y = 1, y(1) = 2.

Thanks, in advance. - Jun 15th 2009, 09:00 PMpickslides

These quations aren't very weird at all. You need to use the integrating factor method for both. They just need a little re-arranging first.

$\displaystyle xy' + 3y = x^7$

divide both sides by x

$\displaystyle y' + \frac{3}{x}y = x^6$

Then follow the steps in this post

http://www.mathhelpforum.com/math-he...equations.html - Jun 15th 2009, 09:46 PMtapiaghector
hey thanks my friend, i have another question, how do you evaluate y'(0) = 3?

- Jun 15th 2009, 11:07 PMmr fantastic
- Jun 16th 2009, 03:56 PMpickslides