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Thread: By comparing areas find the value of a log

  1. June 15th 2009, 03:34 AM #1
    Robb
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    By comparing areas find the value of a log

    By comparing areas, show that
    \frac{1}{3}<\ln 1.5 < \frac{5}{12}
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  2. June 15th 2009, 04:01 AM #2
    alexmahone
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    ln 1.5=ln \frac{3}{2}=ln 3-ln 2=\int \frac{1}{x} (from 2 to 3)
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