Thread: By comparing areas find the value of a log

1. By comparing areas find the value of a log

By comparing areas, show that
$\frac{1}{3}<\ln 1.5 < \frac{5}{12}$

2. $ln 1.5=ln \frac{3}{2}=ln 3-ln 2=\int \frac{1}{x}$ (from 2 to 3)