The only solution I can think of right now involves Maclaurin series. Have you learnt that yet?
Then replace with its Maclaurin series:
Replacing ln(x+1) with the McLaurin series, you wll still have a problem with both numerator and denominator going to 0.
So use L'Hopital's rule.
Now the limit, as x goes to 0, of each of those, is 0 so do it again:
The limit, as x goes to 0, of the numerator is 1 while the limit of the denominator is 2. The original limit is 1/2.