Can someone help me with this question dy/dx = [e^y(sin^2x)]/ [y(secx)] I don't need you to solve it, but how would i isolate both terms so that i can integrate? Thanks -John
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Originally Posted by johntuan Can someone help me with this question dy/dx = [e^y(sin^2x)]/ [y(secx)] I don't need you to solve it, but how would i isolate both terms so that i can integrate? Thanks -John Separate variables: $\displaystyle \frac{y}{e^y} dy = \frac{sin^2x}{sec x} dx$
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