the first one:
where , and bounds change as well, and
For the indefinite, Wolfram gives:
integral x/(x^3+1)^2 dx = 1/18 (log(x^2-x+1)+(6 x^2)/(x^3+1)-2 log(x+1)+2 sqrt(3) tan^(-1)((2 x-1)/sqrt(3)))+constant
Pretty messy, but you can use it for the remaining half.
Hope this helps.