Find the exact value of $\displaystyle y'(\frac{\pi}{3})$ for $\displaystyle y=3xtanx$.
I got $\displaystyle y'(\frac{\pi}{3})=12+3\sqrt{3}$.
Is that right?
If you would show me how you arrived at your reslut I would appreciate it.
Find the exact value of $\displaystyle y'(\frac{\pi}{3})$ for $\displaystyle y=3xtanx$.
I got $\displaystyle y'(\frac{\pi}{3})=12+3\sqrt{3}$.
Is that right?
If you would show me how you arrived at your reslut I would appreciate it.
$\displaystyle y'=3x*sec^2x+3*tanx$
$\displaystyle y'(\frac{\pi}{3})=3*\frac{\pi}{3}*\frac{1}{[cos(\frac{\pi}{3})]^2}+3*tan(\frac{\pi}{3})$
$\displaystyle =\pi*4+3*\sqrt{3}$
$\displaystyle =4\pi+3\sqrt{3}$
It looks as if I may have found my problem for this one.
Is this right?