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Math Help - Evaluating a Derivative at a Given point

  1. #1
    No one in Particular VonNemo19's Avatar
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    Evaluating a Derivative at a Given point

    Find the exact value of y'(\frac{\pi}{3}) for y=3xtanx.

    I got y'(\frac{\pi}{3})=12+3\sqrt{3}.

    Is that right?

    If you would show me how you arrived at your reslut I would appreciate it.
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  2. #2
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    Quote Originally Posted by VonNemo19 View Post
    Find the exact value of y'(\frac{\pi}{3}) for y=3xtanx.

    I got y'(\frac{\pi}{3})=12+3\sqrt{3}.

    Is that right?

    If you would show me how you arrived at your reslut I would appreciate it.
    Again, you won't show your work? No, that is not correct.
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  3. #3
    No one in Particular VonNemo19's Avatar
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    Quote Originally Posted by HallsofIvy View Post
    Again, you won't show your work? No, that is not correct.

    y'=3x*sec^2x+3*tanx

    y'(\frac{\pi}{3})=3*\frac{\pi}{3}*\frac{1}{[cos(\frac{\pi}{3})]^2}+3*tan(\frac{\pi}{3})

    =\pi*4+3*\sqrt{3}

    =4\pi+3\sqrt{3}

    It looks as if I may have found my problem for this one.

    Is this right?
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by VonNemo19 View Post
    y'=3x*sec^2x+3*tanx

    y'(\frac{\pi}{3})=3*\frac{\pi}{3}*\frac{1}{[cos(\frac{\pi}{3})]^2}+3*tan(\frac{\pi}{3})

    =\pi*4+3*\sqrt{3}

    =4\pi+3\sqrt{3}

    It looks as if I may have found my problem for this one.

    Is this right?
    yup
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