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Math Help - Intergration by parts

  1. #1
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    Intergration by parts

    Can someone please check that i am doing this correctly
    \int \ 5xe^{4x}
    Let u = 5x
    v= e^{4x}/4
    du/dx = 5
    dv/dx = e^{4x}
    So 5x . e^{4x}/4 - \int e^{4x}/4 . 5 dx
    then  \frac {\ 5xe^{4x}} {4} - \frac {5e^{4x}} {16}
    So factorised:
     \frac {\ 5e^{4x}} {4} x (x - 1/4) + c
    Cheers
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  2. #2
    MHF Contributor alexmahone's Avatar
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