Find the shortest distance from the point(2,-2,3) to the plane 6x+4y-3z = 2.
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Refer Point-Plane Distance -- from Wolfram MathWorld $\displaystyle D={\frac{|6(2)+4(-2)-3(3)-2|}{\sqrt{6^2+4^2+3^2}}}$ $\displaystyle D=\frac{7}{\sqrt{61}}$
Originally Posted by Link88 Find the shortest distance from the point(2,-2,3) to the plane 6x+4y-3z = 2. Read this: Point-Plane Distance -- from Wolfram MathWorld
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