Nice question indeed
Last edited by a.h.m.a.d; Jun 11th 2009 at 03:26 AM.
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$\displaystyle \int_{0}^{x} \frac{\sin(x)}{\cos(x)}\sqrt{\cos(x)} \ln(\cos(\theta)) x dx=\ln(\cos(\theta))\int_{0}^{x}\frac{\sin{x}}{\sq rt{\cos{x}}}x dx$ The integral beats me
Originally Posted by Ruun $\displaystyle \int_{0}^{x} \frac{\sin(x)}{\cos(x)}\sqrt{\cos(x)} \ln(\cos(\theta)) x dx=\ln(\cos(\theta))\int_{0}^{x}\frac{\sin{x}}{\sq rt{\cos{x}}}x dx$ Originally Posted by Ruun The integral beats me no no no ln(\cos(\theta)) x it is one Function
http://integrals.wolfram.com/index.jsp?expr=sin(x)cos(x)^(-1%2F2)x&random=false I suppose my answer is just wrong lol you mean $\displaystyle \ln(\cos(\theta)x)$? or $\displaystyle \ln(\cos(\theta x))$?
Last edited by Krizalid; Jun 10th 2009 at 03:30 PM.
Originally Posted by Ruun you mean $\displaystyle \ln(\cos(\theta)x)$? or $\displaystyle \ln(\cos(\theta x))$? I Oqsidi ln[(cos theta)x] it is one Function
Originally Posted by a.h.m.a.d Nice question indeed Something looks peculiar here. You're integerating with respect to x and yet there's an x in the upper limit??
Originally Posted by Danny Something looks peculiar here. You're integerating with respect to x and yet there's an x in the upper limit?? I'm sorry I have amended the Annex
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