# Thread: Need help finding the derivative.

1. ## Need help finding the derivative.

I need to find the Derivative of

$f(x)= x+1/x^2$

Can I do this? $x=1/x^2= x-x^2=-x^2+x=f'(x)= -2x+1$
Thanks

Jason

2. Originally Posted by Darkhrse99
I need to find the Derivative of

$f(x)= x+1/x^2$

Thanks

Jason
$f(x) = x + x^{-2}$

$f'(x)=1 +(-2)x^{-2-1}=1-2x^{-3}$

3. Originally Posted by Darkhrse99
I need to find the Derivative of

$f(x)= x+1/x^2$

Thanks

Jason
You can write this as $f(x)= x + x^{-2}$

Using your normal differential rules this gives you $f'(x)= 1 - 2x^{-3}$

4. Originally Posted by Amer
$f(x) = x + x^{-2}$

$f'(x)=1 +(-2)x^{-2-1}=1-2x^{-3}$
Just beat me to it