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Thread: Evaluate limit?

  1. June 9th 2009, 10:49 PM #1
    fardeen_gen
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    Evaluate limit?

    \lim_{n\rightarrow \infty} \frac{(-2)^n + 3^n}{(-2)^{n + 1} + 3^{n + 1}} is equal to?
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  2. June 9th 2009, 11:30 PM #2
    o_O
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    \frac{(-2)^n + 3^n}{(-2)^{n + 1} + 3^{n + 1}} \cdot {\color{red}\frac{\frac{1}{3^{n}}}{\frac{1}{3^{n}} }}

    = \frac{\left(-\frac{2}{3}\right)^n + 1}{\left(-2\right)\left(-\frac{2}{3}\right)^n + 3 \cdot 1}
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