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Thread: Find set of values of x for which limit = 0?

  1. June 9th 2009, 10:28 PM #1
    fardeen_gen
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    Find set of values of x for which limit = 0?

    If \lim_{n\rightarrow \infty} \frac{1}{\left(\frac{3}{\pi} \arctan 2x\right)^{2n} + 5} = 0, then find the set of values of x.

    Answer:
    Spoiler:
    x\in \left(-\infty, -\frac{\sqrt{3}}{2}\right) \cup \left(\frac{\sqrt{3}}{2}, \infty\right)


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  2. June 10th 2009, 12:49 AM #2
    Ruun
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    You want the absolute value of \left(\frac{3}{\pi} \arctan 2x\right)^{2n}>1 see why?

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