find the limit of $\displaystyle a_n = \frac{2^n}{3^{n+1}}$ as n approaches infinity
L'Hopitals rule wont work here. I do not know what technique to use to find the limit. I can look at the graph and tell that it is converging at 0.
find the limit of $\displaystyle a_n = \frac{2^n}{3^{n+1}}$ as n approaches infinity
L'Hopitals rule wont work here. I do not know what technique to use to find the limit. I can look at the graph and tell that it is converging at 0.