and in the problem . If , then thus
I dont know if this is in the right forum because it involves trig stuff. So mod, feel free to move it.
i was just going through some work on the topic 'area between two curves' and i was given the equations as:
f(x) = sin x, and g(x) = sin(2x), a = 0 and b = 'pi'
The solution states that the intersection point could be found as:
sin x = sin(2x), then x = 'pi' - 2x and hence x = 'pi'/3.
i was wondering could someone show me how the step by step as to how they derived the intersection point? Because i never did trig before
Thanks in advance