I am trying to solve this continuity problem and I might be doing something wrong... could someone please take a gander?
Q: For what value of the constant c is the function f continous on ( -infn, infn) where...
f(x) = ct + 5 if t ε (-inf, 7]
ct^2 - 5 if t ε (7, inf)
I tried to solve for c but I think I missed a step. Here's what I did..
c(7) + 5 = c(7)^2 - 5
7c + 5 = 14c - 5
10/7 = c
any help would be appreciated!
June 7th 2009, 07:52 AM
(7)^2 = 49, not 14.
The idea is correct.
You set the two parts equal to each other, so there isn't a jump.
June 7th 2009, 07:59 AM
matheagle, thank you for pointing out my mistake!
indeed 7^2 ≠ 14 haha
solved answer is 5/21
June 7th 2009, 08:18 AM
It's good that you showed your work.
Too many posters don't do that and it's hard for us to find the errors.
We have no idea where you're stuck if we don't see your work.
And no one should be afraid of making errors, we all do.