How do I get the correct derivative for this function?

$\displaystyle y = \frac{2x-1}{(\sqrt{x+1})}$

I got the first part of $\displaystyle \frac{2}{\sqrt{x+1}}$ but cant seemed to get the second part of it using the quotient rule $\displaystyle \frac{2x-1}{2(x+1)^{3/2}}$

y' in the answer's is supposedly

$\displaystyle y ' = \frac{2}{\sqrt{x+1}}-\frac{2x-1}{2(x+1)^{3/2}}$

Can someone please show me how to get to that using the quotient rule?