# Math Help - dy/dx of 3x^2y^2 + 4 xy^3 = 7

1. ## dy/dx of 3x^2y^2 + 4 xy^3 = 7

I need to determine the dy/dx at the point (1,1) of
3x^2y^2 + 4 xy^3 = 7

Maybe I am too tired but I do not know what I should do!!!
I thought I should just take a partial derivative of y but that is not it and I am lost!!! Please anyone point me in the right direction thanks Frostking

2. $6xy^{2} + 3x^{2}2y \frac {dy}{dx} + 4y^{3} + 4x3y^{2} \frac{dy}{dx} = 0$

then solve for $\frac {dy}{dx}$