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Math Help - dy/dx of 3x^2y^2 + 4 xy^3 = 7

  1. #1
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    dy/dx of 3x^2y^2 + 4 xy^3 = 7

    I need to determine the dy/dx at the point (1,1) of
    3x^2y^2 + 4 xy^3 = 7

    Maybe I am too tired but I do not know what I should do!!!
    I thought I should just take a partial derivative of y but that is not it and I am lost!!! Please anyone point me in the right direction thanks Frostking
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  2. #2
    Super Member Random Variable's Avatar
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     6xy^{2} + 3x^{2}2y \frac {dy}{dx} + 4y^{3} + 4x3y^{2} \frac{dy}{dx} = 0

    then solve for  \frac {dy}{dx}
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