The variables u and v take positive values such that 1/u + 1/v = 1/20. If s = u + v, find the least value of s as u varies. Thanks
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Originally Posted by puggie The variables u and v take positive values such that 1/u + 1/v = 1/20. If s = u + v, find the least value of s as u varies. Thanks I don't really see how this is a differentiation problem. . So . Therefore and . Solving these equations simultaneously gives... This value does not have a solution... (check it's discriminant).
Originally Posted by puggie The variables u and v take positive values such that 1/u + 1/v = 1/20. If s = u + v, find the least value of s as u varies. Thanks find and minimize
Originally Posted by Prove It I don't really see how this is a differentiation problem. . So . Therefore and . You are arguing that because a/b= c/d, "therefore" a= c and b= d. That is not true! 2/4= 1/2 but and . Solving these equations simultaneously gives... This value does not have a solution... (check it's discriminant).
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