Hello,
I have this problem..
x = et - 4
y = e2t
Eliminate the parameter and find the Cartesian equation of the curve.
y = ?
So far I have gotten
y = exp(8) * exp(2 ln x)
but It says I am wrong. Can anyone else verify?
Thanks in advance!
Hello,
I have this problem..
x = et - 4
y = e2t
Eliminate the parameter and find the Cartesian equation of the curve.
y = ?
So far I have gotten
y = exp(8) * exp(2 ln x)
but It says I am wrong. Can anyone else verify?
Thanks in advance!
$\displaystyle x = e^t - 4 \Rightarrow x + 4 = e^t \Rightarrow (x + 4)^2 = e^{2t}$ .... (1)
$\displaystyle y = e^{2t}$ .... (2)
Add equations (1) and (2) together.
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$\displaystyle x = e^{t - 4} = e^t e^{-4} \Rightarrow e^4 x = e^t \Rightarrow e^8 x^2 = e^{2t}$ .... (1)
$\displaystyle y = e^{2t}$ .... (2)
Add equations (1) and (2) together.