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Math Help - Triple integration

  1. #1
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    Triple integration



    I integrated w/ respect to x and got 5xze^-y^2. Plugging in the limits of integration, I got 5yze^-y^2. Then integrating with respect to y, I got 5xe^-y^2/-2y. Plugging in the limits of integration, I then get: 5xe^-z^2/-2z. Am I on the right track?
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  2. #2
    MHF Contributor matheagle's Avatar
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    5xe^-y^2/-2y, is wrong.

    \int ye^{-y^2}dy needs to be solved via substitution.

    Let u=-y^2.
    Last edited by matheagle; June 7th 2009 at 07:45 PM.
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  3. #3
    Senior Member Spec's Avatar
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    Quote Originally Posted by juicysharpie View Post


    I integrated w/ respect to x and got 5xze^-y^2. Plugging in the limits of integration, I got 5yze^-y^2. Then integrating with respect to y, I got 5xe^-y^2/-2y. Plugging in the limits of integration, I then get: 5xe^-z^2/-2z. Am I on the right track?
    Almost (note the blue part that I added).


    \int 5z\cdot ye^{-y^2}dy=5z\cdot -\frac{e^{-y^2}}{2}
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