just need some help with these if i integrate
5
x
do i just end up with x
and second i have
4
cube root x^2
the 4 and the x^2 mess things up for me and i dont know what to do
and if i have
1
cube root x
i get
3x^2/3
2
thank you for any help
Hi there
Wow, that is very hard to read
1) $\displaystyle \int \frac 5 x dx = 5 \int \frac 1 x dx = 5 ln|x| + CONST$
2) $\displaystyle \int \frac{4}{\sqrt[3]{x^2}} dx = 4 \int \frac 1 x^{2/3} dx$
$\displaystyle = 4 \int x^{-2/3} dx = 4 * 3 * x^{1/3} + CONST$
Done
Yours,
Rapha
Read this thread: http://www.mathhelpforum.com/math-he...-tutorial.html