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Math Help - local extrema

  1. #1
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    local extrema

    Hi, I don't know how to find the local extrema, and I'm not sure if I differentiated correctly. for the first one is it -ln [(1-x)^2]-2? how do I find the critical point by letting it 0 =S would somebody be able to show me full solutions for part and b please?
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  2. #2
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    part b) f(x) = cos(2x)+ sin(x)

    f'(x) = cos(x)- 2sin(2x)

    for extreme value

    0 = cos(x)-2sin(2x)

    0 = cos(x)-2\times 2sin(x)cos(x)

    0 = cos(x)-4sin(x)cos(x)

    0 = cos(x)(1-4sin(x))

    0 = 1-4sin(x)

    1 = 4sin(x)

    sin(x)=\frac{1}{4}

    can you solve from here?
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