Results 1 to 4 of 4

Math Help - Area bounded by...

  1. #1
    Newbie
    Joined
    May 2009
    Posts
    8

    Area bounded by...

    Area of region bounded by the graphs of x = y^2 and x = y+ 2

    graph the area bounded by y= x^2 + 1 and y = -x + 3
    find the volume of the solid formed by revolving the area about the x-axis.

    harder ones i assume?
    graph the area bounded by x = y^2 + 1 and x = 3

    graph the area bounded by x-axis, y-axis and y = e -2x in the 1st quadrant fidn teh area?

    graph the area bounded by y= 1 x=4 and y = radical x..

    use disc or washer method?
    find all the radiuses..
    use integration to find the volume.

    im so clueless on how to start.. i haven't been to class for a while due to surgery on my knee and missed out a lot and we are having finals soon and im so clueless.. any help would be very much appreciated thanks guys!
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Joined
    Aug 2007
    From
    USA
    Posts
    3,110
    Thanks
    2
    Were you a dummie BEFORE you missed class? Change your screen name and maybe it will help your confidence.

    "Area Between" or "Bounded by" ...

    Find the intersections and decide which is farther from the pertinent axis.

    x = y^2 vs. x = y+2

    Intersections:

    y^2 = y + 2
    y^2 - y - 2 = 0
    (y-2)(y+1)=0
    y = 2 or y = -1

    Which is farther from the Y-Axis?

    y = 0 is in the Range

    0^2 = 0 and 0+2 = 2, so the linear piece is farther away.

    \int_{-1}^{2}(y+2)-(y^{2})\;dy
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    May 2009
    Posts
    8
    yeah i guess yur right...

    anyway.. can someone help out with the other problems im trying to do it and i seem to get stuck in the middle.
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor Amer's Avatar
    Joined
    May 2009
    From
    Jordan
    Posts
    1,093
    Quote Originally Posted by CalculusDUMMIE View Post

    graph the area bounded by y= x^2 + 1 and y = -x + 3

    do you know how to graph a curve ??

    first as TKHunny said you should find the point of intersection

    x^2+1=-x+3

    [tex]x^2+x-2=0[tex]

    by..quadratic..equation

    \frac{-b\mp\sqrt{b^2-4ac}}{2a}.......for......ax^2+bx+c=0....
    you know it right
    you will find the points is

    \frac{-1+\sqrt{9}}{2}....and...\frac{-1-\sqrt{9}}{2}

    the...point...of...intersection...(1)..(-2)

    do you know how to graph y=x^2 if you know to how graph it just bush it up one unit like the graph below the second one is easier



    Area bounded by...-graph.jpg

    and add y=-x+3 so you will have this

    Area bounded by...-graph2.jpg
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Area bounded by given curves
    Posted in the Calculus Forum
    Replies: 3
    Last Post: January 30th 2010, 11:03 AM
  2. area bounded by two curves
    Posted in the Calculus Forum
    Replies: 6
    Last Post: August 19th 2009, 06:29 PM
  3. Bounded area (again)
    Posted in the Calculus Forum
    Replies: 1
    Last Post: May 30th 2009, 04:59 AM
  4. Area Bounded..
    Posted in the Calculus Forum
    Replies: 4
    Last Post: January 18th 2009, 12:09 PM
  5. Area bounded by two curves
    Posted in the Calculus Forum
    Replies: 4
    Last Post: June 23rd 2008, 07:34 PM

Search Tags


/mathhelpforum @mathhelpforum