Find dy/dx for the following curve: x = ( 1 - a sq ) to the power of 3/2 y = sin to the power of -1 ( a )
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can you confirm the equations Looks like,
Last edited by pickslides; Jun 3rd 2009 at 12:33 AM. Reason: typo
Originally Posted by puggie Find dy/dx for the following curve: x = ( 1 - a sq ) to the power of 3/2 y = sin to the power of -1 ( a ) As I said in your last post, this requires Parametric Differentiation. Remember, Is it differentiating the equations themselves you are struggling with?
Hi pickslides y as you have written is correct. x should be a square and not square root of a! The answer is -1/3a(1-a square) Thanks everybody
Substitute
Last edited by alexmahone; Jun 3rd 2009 at 11:11 PM.
from this find from this find
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