Find an equation of the line that is tangent to the graph offand parallel to the given line.

Function:f(x) = 2x^2

Line: 4x–y+ 4 = 0

Tell me what I'm doing wrong. According to my instructor's directions:

Step 1. Find the slope of the tangent line:

Do the algebra, reduces to4x-2h- the limit/slope is 4x.

Step 2. Find the slope of the given line:

4x –y + 4 = 0same asy=4x+4and som=4

Step 3. Set the slope of the tangent equal to the slope of the given line, and solve for x.

4x=4 so x=1

Step 4. Use the values from above to find the equation of the line.

(So elsewhere in the lecture, he mentions that if x=1, then your reference point is (1,1) - if someone else can explain why, I'd appreciate that too. I'm not getting that. But assuming that it is....)

y-1=4(x-1)

y-1=4x-4

y=4x-3

Why isn't this right? What am I missing? I'm sure it's something obvious and dumb?