Find an equation of the line that is tangent to the graph of f for the given value of x.

f(x)=(x^2-3)^5(2x-1)^3 x=2

I got the derivative 2(1-2x)^2(x^2-3)^4(13x^2-5x-9)

Then I plugged in 2 for x and I got 594

I'm not sure if this is right and where to go next..thanks