now
the equation of the tangent
Find an equation of the line that is tangent to the graph of f for the given value of x.
f(x)=(x^2-3)^5(2x-1)^3 x=2
I got the derivative 2(1-2x)^2(x^2-3)^4(13x^2-5x-9)
Then I plugged in 2 for x and I got 594
I'm not sure if this is right and where to go next..thanks