typo
Find the equation for the to the given curve at the point where x = X₀
y=(x^2+3x-1)(2-x); X₀=1
I found the first derivative which came out to:
-x^2-3x+(2-x)(2x+3)+1
simplified to:
-3x^2-2x+7
then I set f( X₀)=1 to f( X₀)=(1)=2
Then I plugged it in my equation:
-3(1^2)-2(1)+7=2
I'm not sure if I'm doing it right and i'm not sure how to finish it. Thanks!