Thread: calculate

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the first one substitute u=cosx the other tan^2x+1=sec^x .... tan^2x=sec^2-1 and now the integrate for sec^2x =tanx and integrate of -1 =-x

thats all

they cannot multiply and divide on 1-sinx; because 1-sinx is can equal to zero
thankyou

help: let us pose t= Tan(x/2)

you know the answer right ??

but if you derive my answer you will get the integral I try it I think there is no problem if I multiply with 1-sinx

or if the integral have limits then we should look at the interval [0,pi/2]
I cant multiply with 1-sinx or 1-cosx or 1-tanx .....

Originally Posted by Amer

you know the answer right ??

but if you derive my answer you will get the integral I try it I think there is no problem if I multiply with 1-sinx

or if the integral have limits then we should look at the interval [0,pi/2]
I cant multiply with 1-sinx or 1-cosx or 1-tanx .....

remark : 1-sinx=0
sinx=1
x=pi/2?????

I know I ask if the integral have not limits then I can multiply with 1-sinx